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amtalx
Apr 1, 2008, 02:04 PM
What should I do with my 3000th post?

PhotonDrop
Apr 1, 2008, 02:47 PM
Do something productive.

Randomness
Apr 1, 2008, 02:55 PM
You forgot to put e as an option. How dare you offer pi without e!

amtalx
Apr 1, 2008, 02:59 PM
Pi without e is just Pi. Pi with e is Pie.

Coincidence? I think not.

HAYABUSA-FMW-
Apr 1, 2008, 03:30 PM
On 2008-04-01 12:04, amtalx wrote:
What should I do with my 3000th post?

Hide it from the space men.

Skuda hid his for a while. Didn't know where it was let go.

Wyndham
Apr 1, 2008, 03:31 PM
let's party like it's 2999.

Randomness
Apr 1, 2008, 03:36 PM
On 2008-04-01 12:59, amtalx wrote:
Pi without e is just Pi. Pi with e is Pie.

Coincidence? I think not.



e is superior to pi, pi is unnecessary and foreign.

HAYABUSA-FMW-
Apr 1, 2008, 03:46 PM
On 2008-04-01 13:36, Randomness wrote:
e is superior to pi, pi is unnecessary and foreign.

Right, like colon E which is kinda catty or even Talon who even went "nya," so you actually don't like the e?

Nitro Vordex
Apr 1, 2008, 05:27 PM
Hm.

http://img166.imageshack.us/img166/4600/somesplaininxz6.png

Looks like you got some explaining to do.

Bot-Bot
Apr 1, 2008, 06:18 PM
e^(pi*i) + 1 = 0

Greatest ever.

Nitro Vordex
Apr 1, 2008, 06:19 PM
Post a review of my story, that's what. ;(

Randomness
Apr 1, 2008, 06:21 PM
On 2008-04-01 16:18, Bot-Bot wrote:
e^(pi*i) + 1 = 0

Greatest ever.



Pretty sure its not quite that... pi is equal to -i over the log base -1 of e... I'm having trouble reconciling the two.

Bot-Bot
Apr 1, 2008, 06:50 PM
On 2008-04-01 16:21, Randomness wrote:

On 2008-04-01 16:18, Bot-Bot wrote:
e^(pi*i) + 1 = 0

Greatest ever.



Pretty sure its not quite that... pi is equal to -i over the log base -1 of e... I'm having trouble reconciling the two.


To start off, punch that into your graphing calculator, if you have one. It works.

Also my friend explained it to me, and I will do my best to return the favor to you.

e^(pi*i) + 1 = 0

e^(pi*i) = -1

[Take Natural Log of both sides]
ln(e^(pi*i)) = ln(-1)

[When dealing with non-real numbers ln(-1)=(pi*i)]

[ln and e cancel each other out]
ln(e^(pi*i)) = (pi*i)

[Simplify]
(pi*i) = (pi*i)

Randomness
Apr 1, 2008, 07:09 PM
On 2008-04-01 16:50, Bot-Bot wrote:
To start off, punch that into your graphing calculator, if you have one. It works.

Also my friend explained it to me, and I will do my best to return the favor to you.

I never said you were wrong. I was saying I couldn't reconcile your equation with mine.

-
Sheesh with the requote the whole quotes!

<font size=-1>[ This Message was edited by: HAYABUSA-FMW- on 2008-04-01 17:13 ]</font>

HAYABUSA-FMW-
Apr 1, 2008, 07:13 PM
That goes without saying.

Bot-Bot
Apr 1, 2008, 07:13 PM
Oh well... sorry.

amtalx
Apr 1, 2008, 10:41 PM
On 2008-04-01 15:27, Nitro_Vordex wrote:
Hm.

http://img166.imageshack.us/img166/4600/somesplaininxz6.png

Looks like you got some explaining to do.



MODH4X

I call Shenanigans.

Weeaboolits
Apr 1, 2008, 11:09 PM
lrn2math

HAYABUSA-FMW-
Apr 2, 2008, 12:32 AM
Shadowpawn might write:
olomathpostfight

amtalx
Apr 2, 2008, 06:39 AM
BACK ON TOP BABY.