View Full Version : OMG its 2999
amtalx
Apr 1, 2008, 02:04 PM
What should I do with my 3000th post?
PhotonDrop
Apr 1, 2008, 02:47 PM
Do something productive.
Randomness
Apr 1, 2008, 02:55 PM
You forgot to put e as an option. How dare you offer pi without e!
amtalx
Apr 1, 2008, 02:59 PM
Pi without e is just Pi. Pi with e is Pie.
Coincidence? I think not.
HAYABUSA-FMW-
Apr 1, 2008, 03:30 PM
On 2008-04-01 12:04, amtalx wrote:
What should I do with my 3000th post?
Hide it from the space men.
Skuda hid his for a while. Didn't know where it was let go.
Wyndham
Apr 1, 2008, 03:31 PM
let's party like it's 2999.
Randomness
Apr 1, 2008, 03:36 PM
On 2008-04-01 12:59, amtalx wrote:
Pi without e is just Pi. Pi with e is Pie.
Coincidence? I think not.
e is superior to pi, pi is unnecessary and foreign.
HAYABUSA-FMW-
Apr 1, 2008, 03:46 PM
On 2008-04-01 13:36, Randomness wrote:
e is superior to pi, pi is unnecessary and foreign.
Right, like colon E which is kinda catty or even Talon who even went "nya," so you actually don't like the e?
Nitro Vordex
Apr 1, 2008, 05:27 PM
Hm.
http://img166.imageshack.us/img166/4600/somesplaininxz6.png
Looks like you got some explaining to do.
Bot-Bot
Apr 1, 2008, 06:18 PM
e^(pi*i) + 1 = 0
Greatest ever.
Nitro Vordex
Apr 1, 2008, 06:19 PM
Post a review of my story, that's what. ;(
Randomness
Apr 1, 2008, 06:21 PM
On 2008-04-01 16:18, Bot-Bot wrote:
e^(pi*i) + 1 = 0
Greatest ever.
Pretty sure its not quite that... pi is equal to -i over the log base -1 of e... I'm having trouble reconciling the two.
Bot-Bot
Apr 1, 2008, 06:50 PM
On 2008-04-01 16:21, Randomness wrote:
On 2008-04-01 16:18, Bot-Bot wrote:
e^(pi*i) + 1 = 0
Greatest ever.
Pretty sure its not quite that... pi is equal to -i over the log base -1 of e... I'm having trouble reconciling the two.
To start off, punch that into your graphing calculator, if you have one. It works.
Also my friend explained it to me, and I will do my best to return the favor to you.
e^(pi*i) + 1 = 0
e^(pi*i) = -1
[Take Natural Log of both sides]
ln(e^(pi*i)) = ln(-1)
[When dealing with non-real numbers ln(-1)=(pi*i)]
[ln and e cancel each other out]
ln(e^(pi*i)) = (pi*i)
[Simplify]
(pi*i) = (pi*i)
Randomness
Apr 1, 2008, 07:09 PM
On 2008-04-01 16:50, Bot-Bot wrote:
To start off, punch that into your graphing calculator, if you have one. It works.
Also my friend explained it to me, and I will do my best to return the favor to you.
I never said you were wrong. I was saying I couldn't reconcile your equation with mine.
-
Sheesh with the requote the whole quotes!
<font size=-1>[ This Message was edited by: HAYABUSA-FMW- on 2008-04-01 17:13 ]</font>
HAYABUSA-FMW-
Apr 1, 2008, 07:13 PM
That goes without saying.
Bot-Bot
Apr 1, 2008, 07:13 PM
Oh well... sorry.
amtalx
Apr 1, 2008, 10:41 PM
On 2008-04-01 15:27, Nitro_Vordex wrote:
Hm.
http://img166.imageshack.us/img166/4600/somesplaininxz6.png
Looks like you got some explaining to do.
MODH4X
I call Shenanigans.
Weeaboolits
Apr 1, 2008, 11:09 PM
lrn2math
HAYABUSA-FMW-
Apr 2, 2008, 12:32 AM
Shadowpawn might write:
olomathpostfight
amtalx
Apr 2, 2008, 06:39 AM
BACK ON TOP BABY.
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