How to win at the casino - existentialist time wasting

[PsNiBe]

On 2007-11-25 21:38, Getintothegame wrote:
Just letting you know, I've been looking at patterns for fun on the PSOW cams- they're both resting in the casino. Hope this can help you out a little as well. They'll probably be there quite a lot.

http://www.pso-world.com/cam.php

oh wow nice i didn't know that, thanks

[PsNiBe]

On 2007-11-25 21:34, ZX wrote:
I've found the trick to it. Highest record of wins straight for me have been 27. Don't ask me, I'm not telling you, and flame me all you want. I just wanted to let everyone know that there IS one, so keep trying.

youtube. go. now.

[StKkilo]

ok your cool. you can make up random numbers. look i can do it too!


3452464872364<><R>FR<ATE%e36584564 = wxswqswxswqszqzq12134ewrer5jlo9i8yubvtyrcexrexrwzq zq


=


im cool?

just stop

[StkDrowsy]

wow kilo, where did you get that sick equation.......wow please continue to make therms for us, with his equation i just made my gold coins into dimond coins

[Sharkyland]

This must be the reason why I hate statistics...

[panzer_unit]

You should NEVER consider the un/likelihood of previous results when betting. All of the possible outcomes on the next spin have EXACTLY the same odds of happening regardless of what's come before. That's how a lot of people lose their money, figuring a streak is about to run out.

The most important thing is to start low enough and play the odds so you can afford to keep covering your original bet a reasonable number of times.

[Getintothegame]

Also, NEVER go all in. Use your coin sparingly.

On 2007-11-26 09:37, panzer_unit wrote:
You should NEVER consider the un/likelihood of previous results when betting. All of the possible outcomes on the next spin have EXACTLY the same odds of happening regardless of what's come before. That's how a lot of people lose their money, figuring a streak is about to run out.

See also:

I took the screen a moment too late, but it was all red with the random 0.

It's all chance.

<font size=-1>[ This Message was edited by: Getintothegame on 2007-11-26 10:46 ]</font>

[panzer_unit]

On 2007-11-25 17:55, PsNiBe wrote:
Percent likelyhood of each streak (Color only):
Run of 2: 50% (RR, RB, BR, BB)
Run of 3: 25% (RRR, RRB, RBR, RBB, BBB, BBR, BRB, BRR)
Run of 4: 12.5%
Run of 5: 6.25%
Run of 6: 3.125%
Run of 7: 1.5625%
Run of 8: 0.78125%
Run of 9: 0.390625%

This is actually a really good chart, showing you what the odds are that you'll have to ride out a losing streak of various lengths.

While the odds of preceding events don't matter, using odds to guess a safe number of times you should expect to cover your bet is pretty reasonable. There's a ~3% chance you go broke if you bet high enough that the 6th bet is the last one where you can't double your coins again.

[StKkilo]

On 2007-11-26 11:08, panzer_unit wrote:

On 2007-11-25 17:55, PsNiBe wrote:
Percent likelyhood of each streak (Color only):
Run of 2: 50% (RR, RB, BR, BB)
Run of 3: 25% (RRR, RRB, RBR, RBB, BBB, BBR, BRB, BRR)
Run of 4: 12.5%
Run of 5: 6.25%
Run of 6: 3.125%
Run of 7: 1.5625%
Run of 8: 0.78125%
Run of 9: 0.390625%

This is actually a really good chart, showing you what the odds are that you'll have to ride out a losing streak of various lengths.

While the odds of preceding events don't matter, using odds to guess a safe number of times you should expect to cover your bet is pretty reasonable. There's a ~3% chance you go broke if you bet high enough that the 6th bet is the last one where you can't double your coins again.

that is completely innaccurate. First off. the chances of winning 9 times is not 3%. it doesnt go down by half each time after the first one it is 50% then the color is chnaged and the percent can not be 3%.

N00B

[ShineOnline]

I'm going to try and simplify things a little. If you only bet red or black (it doesn't matter as long as it's a color) your odds of LOSING are always 20/38=0.5263 or 52.63%. To calculate the odds of you losing "n" times IN A ROW, you just raise 0.5263 to the n power.

Odds of losing once in a row = 0.5263^1 = 0.5263 = 52.63%
losing twice in a row = 0.5263^2 = 0.2770 = 27.70%
three times = 0.5263^3 = 0.1458 = 14.58%
4 times = 0.5263^4 = 0.0767 = 7.67%
10 times = 0.5263^10 = 0.001631 = 0.16%

But remember, as previously stated, the odds of losing any specific turn are always 52.63% regardless of what happened on the previous turn.