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There are a rubber band and USB cable on my desk which are aligned in just the right way to form the illusion of an eyeball when I cross my eyes.
Thought you'd like to know.
Limit as h goes to 0 of (f(x+h)-f(x))/h.
<font size=-1>[ This Message was edited by: Randomness on 2008-05-09 20:00 ]</font>
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Me and Al Gore invented the internet way back in the 60s.
Equipped with nothing but a rubber band, a bowl of frosted flakes, and one cat that pissed on everything.
Sadly, I cannot claim to have invented the entire set of real numbers. Nor imaginaries, which can also solve that.On 2008-05-09 20:23, astuarlen wrote:
Hey, you come up with that all by yourself? I invented Fig Newtons.
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e^(i*pi) +1 = 0
if i remember correctly
Hey guys, want to see a magic trick? *disappears for a few years*
About what? That function has as its solution every number in existence. Its one of two basic forms for a derivative that I know.On 2008-05-09 21:23, astuarlen wrote:
Golden. And wet. Wet and golden.On 2008-05-09 20:30, Toadthroat wrote:
Me and Al Gore invented the internet way back in the 60s.
Equipped with nothing but a rubber band, a bowl of frosted flakes, and one cat that pissed on everything.
Randomness, I think you are mistaken.
Coming Soon!
On 2008-05-09 19:58, astuarlen wrote:
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There are a rubber band and USB cable on my desk which are aligned in just the right way to form the illusion of an eyeball when I cross my eyes.
Thought you'd like to know.
Whatever you do, don't stare and cross your eyes at this. It's a breeding ground for insanity.
First, that's awesome. Second, pictures or it never happened.On 2008-05-09 19:58, astuarlen wrote:
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There are a rubber band and USB cable on my desk which are aligned in just the right way to form the illusion of an eyeball when I cross my eyes.
Thought you'd like to know.
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To the right of my computer desktop, there is a 1.5'x5' mirror on my hinged closet door that I use to view a TV that my back faces at a 45 degree angle. I change the channel by pointing the remote at the mirror. Programs requiring reading pose a significant challenge.
I do that right?
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